Question

The oxidation number of Federal in K4[Fe(CN)6] is​

Answer 1

Answer:

As per the formula of the compound, the oxidation number of and 'CN' is 4 and (-6) respectively. Conclusion: From the above calculation it is inferred that the oxidation number of Fe in is +2.

Explanation:

The oxidation number of Fe in K4Fe(CN)6 can be calculated as follows,

4(+1) + x + 6(-1) = 0

Hence x = +2

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Answer 2

Answer:

+2

Explanation:

Let the oxidation number of Fe be x.

Oxidation number of CN=−1, K=+1.

In K

4

[Fe(CN)

6

]: 4×1+x+6×(−1)=0

4+x−6=0 or x=+2

The oxidation state of Fe in K4[Fe(CN) 6 ] is +2.