Chemistry, asked by bynalikitha8109, 1 year ago

The oxidation number of I in HOI is
a) -1
b) 0
c) -2
d) +1

Answers

Answered by aayushmansamal22
2
0
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Answered by gadakhsanket
6

Hey dear,

◆ Answer -

(d) +1

◆ Explanation -

Let x be the oxidation number of I in HOI.

As we know, sum of oxidation states of all entities in compound is equal to its charge.

Given that in HOI,

ON(H) = +1 , ON(O) = -2 , charge = 0

1(+1) + 1(-2) + 1(x) = 0

1 - 2 + x = 0

x = +1

Therefore, oxidation number of I in HOI is +1.

Hope this helped you. Thanks for asking..

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