The oxidation number of I in HOI is
a) -1
b) 0
c) -2
d) +1
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Answered by
2
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Answered by
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Hey dear,
◆ Answer -
(d) +1
◆ Explanation -
Let x be the oxidation number of I in HOI.
As we know, sum of oxidation states of all entities in compound is equal to its charge.
Given that in HOI,
ON(H) = +1 , ON(O) = -2 , charge = 0
1(+1) + 1(-2) + 1(x) = 0
1 - 2 + x = 0
x = +1
Therefore, oxidation number of I in HOI is +1.
Hope this helped you. Thanks for asking..
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