The oxidation number of sulphur in S₈, S₂F₂, H₂S respectively, are
(a) 0, +1 and –2
(b) +2, +1 and –2
(c) 0, +1 and +2
(d) –2, +1 and –2
Answers
Answered by
4
HEY MATE CORRECT ANSWER TO THE QUESTION IS A.
SOLUTION:-
IN BASIC MOLECULAR FORM OXIDATION OF ANY ELEMENT IS O..
AS F IS MOST ELECTRONEGATIVE SO F GETS NEGATIVE AND S GETS 2 +
AND H IS MOSTLY POSITIVE HERE WE MULTIPLY COEFFICIENT TWO AND SULPHUR WOULD BE NEGATIVE ☺
PLEASE MARK AS BRAINLIEST
Answered by
0
Answer:
(a) 0, +1 and –2
Explanation:
S8=0
S2F2=2X-2=0
=1
H2S=X+2=0
=-2
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