Chemistry, asked by shvnbabu6289, 1 year ago

The oxidation number of sulphur in S₈, S₂F₂, H₂S respectively, are
(a) 0, +1 and –2
(b) +2, +1 and –2
(c) 0, +1 and +2
(d) –2, +1 and –2

Answers

Answered by sahil1531
4

HEY MATE CORRECT ANSWER TO THE QUESTION IS A.

SOLUTION:-

IN BASIC MOLECULAR FORM OXIDATION OF ANY ELEMENT IS O..

AS F IS MOST ELECTRONEGATIVE SO F GETS NEGATIVE AND S GETS 2 +

AND H IS MOSTLY POSITIVE HERE WE MULTIPLY COEFFICIENT TWO AND SULPHUR WOULD BE NEGATIVE ☺

PLEASE MARK AS BRAINLIEST

Answered by chagsamyuktha
0

Answer:

(a) 0, +1 and –2

Explanation:

S8=0

S2F2=2X-2=0

=1

H2S=X+2=0

=-2

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