Question

The oxidation state of cr in [cr(NH3)4cl2] + is​

Answer 1

$\mathfrak{\huge{\green{\underline{\underline{Answer :}}}}}$

Oxidation number of Cr in [Cr[NH3]4Cl2]+ is +3 x+(4×0)+(−1×2)=+1 x−2=+1 x= +3.

Answer 2

Answer:

+3

Oxidation number of Cr in [Cr[NH

3

]

4

Cl

2

]

+

is +3

x+(4×0)+(−1×2)=+1

x−2=+1

x=+3

hope it helps!

by shagun