Question

The oxidation state of phosphorous is minimum in
(A) P4O6
(B) NaH2PO2(C) PH3 (D)Na3PO4​

Answer 1

Hi there,

The answer is C= PH3

The oxidation state for compounds

O= -2

Na = +1

H= +1

A) P4O6

P= 2×6 ÷4 = +3

B) NaH2PO2

P= 2×2 - 3 = +1

C) PH3

P = -3

D) Na3PO4

P= 2×4 - 3 = +5

The minimum is 《C》

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Answer 2

Answer:

c

Explanation:

P4O6

LET P IS X IN ALL

4X - 2×6=0

SO X = 12 /4

X =3

NAH2PO3

1+1×2+X+-2×3=0

1+2+X-6=0

SO X= 3

PH3

X+3=0

X= --3

NA3PO4

1×3+X+(-2)×4=0

3+X-8=0

X= 5

SO C IS CORRECT ANSWER