Chemistry, asked by valancy7011, 10 months ago

The oxidation states of sulphur in the anions SO₃²⁻, S₂O₄²⁻
and S₂O₆ follow the order
(a) S₂O₆²⁻ < S₂O₄²⁻ < SO₃²⁻
(b) S₂O₄²⁻ < SO₃²⁻ < S₂O₆²⁻
(c) SO₃²⁻ < S₂O₄²⁻ < S₂O₆²⁻
(d) S₂O₄²⁻ < S₂O₆²⁻ < SO₃²⁻

Answers

Answered by Anonymous
9

⚠️Hope this helps you ⚠️

The oxidation states of sulphur in the anions SO₃²⁻, S₂O₄²⁻

and S₂O₆ follow the order

(a) S₂O₆²⁻ < S₂O₄²⁻ < SO₃²⁻

(b) S₂O₄²⁻ < SO₃²⁻ < S₂O₆²⁻

(c) SO₃²⁻ < S₂O₄²⁻ < S₂O₆²⁻

(d) S₂O₄²⁻ < S₂O₆²⁻ < SO₃²⁻

Answered by Anonymous
0

Answer:

(d)s204²-<s206²-<so3²-

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