Find the number of terms from 1 to 1000, which is divisible by 7
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142
the ans is attached above An is highest 3 digit number divisible by 7
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we can see that all multiples of 7 forms an A.P.
in this A.P.
a= 7
= 994(largest number inside 1000 which is divisible by 7)
d = 7
now we need to find the number of terms n
=a +(n-1)d
994 = 7 +(n-1)7
994-7= 7n-7
994 = 7n ( cancelling both -7)
142 = n
therefore there are 142 terms divisible by 7 inside 1- 1000
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