The pages of a book are numbered consecutively: 1, 2, 3, 4 and so on. No pages are missing. If in the page numbers the digit 3 occurs exactly 99 times, what is the number of the last page?
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page numbers with the digit 3 occurring in them are :
03, 13, 23, 30, 31,32,33, 34, 35, 36, 37, 38, 39, ,43,53, 63, 73,83,93,
1 + 03,13, 23, 30, 31, 32, 33, 34,35, 36, 37, 38, 39, 43, 53, 63, 73, 83, 93,
2 +
3 +
4 + ...
so from 00 to 99: we have 20 of digit 3.
100 to 199 20 total up to 199 : 40
200 to 299 : 20 total up to 299: 60
300 to 399 : 20 + 100 total up to 399 : 180
From 300: 309 : we have 10 so total 70 of digit 3.
310 to 319 : 10 : 80
320 to 329 : 10: 90
So now, 330, 331, 332, 333, : there are 9 of the digit 3.
So the answer is 333.
03, 13, 23, 30, 31,32,33, 34, 35, 36, 37, 38, 39, ,43,53, 63, 73,83,93,
1 + 03,13, 23, 30, 31, 32, 33, 34,35, 36, 37, 38, 39, 43, 53, 63, 73, 83, 93,
2 +
3 +
4 + ...
so from 00 to 99: we have 20 of digit 3.
100 to 199 20 total up to 199 : 40
200 to 299 : 20 total up to 299: 60
300 to 399 : 20 + 100 total up to 399 : 180
From 300: 309 : we have 10 so total 70 of digit 3.
310 to 319 : 10 : 80
320 to 329 : 10: 90
So now, 330, 331, 332, 333, : there are 9 of the digit 3.
So the answer is 333.
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