Question

The paint in a certain container is sufficient to paint an area equal to 9.375 m². How many bricks of dimensions 22.5 cm X 10 cm X 7.5 cm can be painted out of this container?

please fasttt give me correct..i will mark as brainlist....​

Answer 1

${\large{\pmb{\sf{\underline{\maltese \: \: Understanding \; the \; question}}}}}$

★ This question says that we have to find out the area that how many bricks of dimensions 22.5 cm × 10 cm × 7.5 cm can be painted out of this container. Means the length of the brick is 22.5 cm, breadth is 10 cm and th height is 7.5 cm. And also given that paint in a certain container is sufficient to paint an area equal to 9.375 metres². Means 9.375 is the total surface area of th brick here. Bricks are in the shape of cuboid. Let's solve this question!

${\large{\pmb{\sf{\underline{\maltese \: \: Answer}}}}}$

• The number of bricks that can be painted out of this container = 100 bricks.

${\large{\pmb{\sf{\underline{\maltese \: \: Given \; that}}}}}$

• Dimensions of the bricks = 22.5 cm × 10 cm × 7.5 cm.

• Total surface area of the brick = 9.375 metres².

${\large{\pmb{\sf{\underline{\maltese \: \: To \; find}}}}}$

• The area that how many bricks of dimensions 22.5 cm × 10 cm × 7.5 cm can be painted out of this container.

${\large{\pmb{\sf{\underline{\maltese \: \: Using \; concepts}}}}}$

Formula to find out that how many of the number of bricks that can be painted out of this container(according to the question).

Formula to find the area that can be painted using the container.

${\large{\pmb{\sf{\underline{\maltese \: \: Using \; formulas}}}}}$

${\small{\underline{\boxed{\sf{\rightarrow Number \: of \: bricks \: = \dfrac{Area \: that \: can \: be \: painted \dots}{TSA \: of \: brick}}}}}}$

${\small{\underline{\boxed{\sf{\rightarrow Area \: that \: can \: be \: painted \dots \: = Have \: to \: convert \: TSA \: into \: area \: without \: decimal}}}}}$

${\large{\pmb{\sf{\underline{\maltese \: \: Full \; Solution}}}}}$

~ As the total surface area of the bricks are already given that's why there is no need to find out it. It is given as indirectly as the paint in a certain container is sufficient to paint an area equal to 9.375 m². But if you want to find it then you can, wait let me tell how to find!

${\small{\underline{\boxed{\sf{\rightarrow TSA \: = 2(lb+bh+lh)}}}}}$

${\sf{\mapsto TSA \: = 2(lb+bh+lh)}}$

${\sf{\mapsto TSA \: = 2(22.5×10 + 10×7.5 × 22.5×7.5)}}$

${\sf{\mapsto TSA \: = 2(225+75+168.75)}}$

${\sf{\mapsto TSA \: = 2(468.75)}}$

${\sf{\mapsto TSA \: = 2 \times 468.75}}$

${\sf{\mapsto TSA \: = 9.375 m^{2}}}$

~ Now as its given that some units are in cm and some in m. So let's convert it into centimetres now.

${\sf{\mapsto 1 \: m \: = 100 \: cm}}$

${\sf{\mapsto 9.375 \times 100}}$

${\sf{\mapsto 93750 \: cm^{2}}}$

~ Now let's find the number of bricks that can be painted out of this container!

${\small{\underline{\boxed{\sf{\rightarrow Number \: of \: bricks \: = \dfrac{Area \: that \: can \: be \: painted \dots}{TSA \: of \: brick}}}}}}$

${\sf{\mapsto Number \: of \: bricks \: = \dfrac{Area \: that \: can \: be \: painted \dots}{TSA \: of \: brick}}}$

${\sf{\mapsto Number \: of \: bricks \: = \dfrac{93750}{9.375}}}$

${\sf{\mapsto Number \: of \: bricks \: = 100}}$

Henceforth, 100 numberof bricks are the number of bricks that can be painted out of the container.

Answer 2

Answer:

As the total surface area of the bricks are already given that's why there is no need to find out it. It is given as indirectly as the paint in a certain container is sufficient to paint an area equal to 9.375 m². But if you want to find it then you can, wait let me tell how to find!

{\small{\underline{\boxed{\sf{\rightarrow TSA \: = 2(lb+bh+lh)}}}}}

→TSA=2(lb+bh+lh)

{\sf{\mapsto TSA \: = 2(lb+bh+lh)}}↦TSA=2(lb+bh+lh)

{\sf{\mapsto TSA \: = 2(22.5×10 + 10×7.5 × 22.5×7.5)}}↦TSA=2(22.5×10+10×7.5×22.5×7.5)

{\sf{\mapsto TSA \: = 2(225+75+168.75)}}↦TSA=2(225+75+168.75)

{\sf{\mapsto TSA \: = 2(468.75)}}↦TSA=2(468.75)

{\sf{\mapsto TSA \: = 2 \times 468.75}}↦TSA=2×468.75

{\sf{\mapsto TSA \: = 9.375 m^{2}}}↦TSA=9.375m

2

~ Now as its given that some units are in cm and some in m. So let's convert it into centimetres now.

{\sf{\mapsto 1 \: m \: = 100 \: cm}}↦1m=100cm

{\sf{\mapsto 9.375 \times 100}}↦9.375×100

{\sf{\mapsto 93750 \: cm^{2}}}↦93750cm

2

~ Now let's find the number of bricks that can be painted out of this container!

{\small{\underline{\boxed{\sf{\rightarrow Number \: of \: bricks \: = \dfrac{Area \: that \: can \: be \: painted \dots}{TSA \: of \: brick}}}}}}

→Numberofbricks=

TSAofbrick

Areathatcanbepainted…

{\sf{\mapsto Number \: of \: bricks \: = \dfrac{Area \: that \: can \: be \: painted \dots}{TSA \: of \: brick}}}↦Numberofbricks=

TSAofbrick

Areathatcanbepainted…

{\sf{\mapsto Number \: of \: bricks \: = \dfrac{93750}{9.375}}}↦Numberofbricks=

9.375

93750

{\sf{\mapsto Number \: of \: bricks \: = 100}}↦Numberofbricks=100

Henceforth, 100 numberof bricks are the number of bricks that can be painted out of the container.