the paint in the certain container is sufficient to paint an area equal to 9375sqcm.How many bricks of dimensions 22.5 cm x 10 cm x 7.5 cm can be painted out of this container?
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3
total surface area of brick =
168.75 cm
Req no of brick = volume of paint contained / tsa of brick
9375/168.75
168.75 cm
Req no of brick = volume of paint contained / tsa of brick
9375/168.75
lambture:
55.55 is it the right answer
Heya no its wrong i hav done a mistake....in hurry
please could u ans the r8
U should divide tsa of brick by volume of paint contained..... N the point is that brick could not be in decimal... Question is asking req no of brick
i got the ans its actually 10
no of required bricks is 10
well thnx
Sorry in hurry i hav answered u wrongly
Tsa bhi galat nikala tha maine issly ans nhi aa rha tha ......
Answered by
4
TSA of brick = 2[(22.5*10)+(22.5*7.5)+(7.5*10)
= 2[225+168.75+75]
= 2*468.75
= 937.5 cm^2
n=no: of bricks
9375 = n*937.5
n = 9375 / 937.5 = 10
= 2[225+168.75+75]
= 2*468.75
= 937.5 cm^2
n=no: of bricks
9375 = n*937.5
n = 9375 / 937.5 = 10
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