The pair of equations 2x-5y+4=0 and 2x+y-8=0 has
(1 Point)
Answers
Answer:
the pair of equations has unique solution because a1/a2 is not equal to b1/b2
Question- The pair of equations 2x-5y+4=0 and 2x+y-8=0 has (a) a unique solution (c) infinitely many solutions (b) exactly two solutions (d) no solution
The pair of equations 2x-5y+4=0 and 2x+y-8=0 has a unique solution. (Option a)
Given:
Equation: 2x-5y+4=0 and 2x+y-8=0
To find:
The number of solutions
Solution:
We can express the given equations in the following form-
a1x+b1y+c1=0
a2x+b2y+c2=0
On comparing with the given equations, the values are as follows-
a1=2, b1= -5, and c1=4
a2=2, b2=1, and c2= -8
Now, we will equate the ratios of a1 and a2, b1 and b2.
Using values,
a1/a2=2/2=1/1
b1/b2= -5/1
So, a1/a2≠b1/b2.
The given pair of equations has only one unique solution.
Therefore, the pair of equations 2x-5y+4=0 and 2x+y-8=0 has a unique solution.
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