Math, asked by VinayakDahiya, 10 months ago

The pair of equations 3x+4y=18 and 4x+16/3y=24 has (a) infinite solutions (b) unique solution (c) no solution (d) cannot say anything please tell the answer its urgent

Answers

Answered by Agastya0606
33

Given: The pair of equations 3x + 4y = 18 and 4x + 16/3y = 24

To find: Choose the correct option:

              (a) infinite solutions

              (b) unique solution

              (c) no solution

              (d) cannot say anything

Solution:

  • Now we have given two equations:

                  3x + 4y = 18 and 4x + 16/3y = 24

  • Lets check for infinitely many solutions, the condition is:

                  a1/a2 = b1/b2 = c1/c2

  • Here a1 = 3, a2 = 4, b1 = 4, b2 = 16/3, c1 = 18, c2 = 24
  • So comparing it, we get:

                  3/4 = 4/(16/3) = 18/24

                  3/4 = 4x3/16 = 18/24

                  3/4 = 3/4 = 3/4

  • So the condition satisfies.
  • The equations are having infinitely many solutions.

Answer:

             So the given pair has (a) infinitely many solutions.

Answered by soumya182009
0

Answer:

(a) infinitely many solutions

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