Question

The pair of linear equations (3k+1)x+3y-5=0 and 2x-3y+5=0 have infinite solutions.Then find the value of k.

Answer 1

infinite sol . means
$\frac{a1}{a2} = \frac{b1}{b2} = \frac{c1}{c2}$
$\frac{3k + 1}{2} = \frac{3}{ - 3}$
3k+1=-2
k=-2-1/3
k=-3/3
k= -1

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