Question

The pair of linear equations (3k + 1)x + 3y –5 = 0 and 2x –3y + 5 = 0 have infinite number of solutions. Then the value of k is

Answer 1

Answer:

-1

Step-by-step explanation:

The linear pairs of equations a

1

x+b

1

y+c

1

=0 and a

2

x+b

2

y+c

2

=0 have infinite solutions if

a

2

a

1

=

b

2

b

1

=

c

2

c

1

Consider the equations (3k+1)x+3y−5=0 and 2x−3y+5=0

⇒

2

3k+1

=

−3

3

=

5

−5

⇒

2

3k+1

=−1

⇒3k+1=−2

⇒3k=−3

∴k=

3

−3

=−1

Hence the value of k=−1