Question

the pair of linear equations 3x/2+5y/3=7 and 9x+10y=14​

Answer 1

Answer: it is consistent

a1/a2  ≠ b1/b2

 Explanation: 3/2x + 5/3y = 7 ; 9x – 10y = 14

                  a1/a2 = 3/2/9 = 1/6

                  b1/b2 = 5/3/–10 = – 1/6 and

                  c1/c2 = 7/14 = 1/2

                  Hence, a1/a2 ≠ b1/b2

                  Therefore, these linear equations intersect each other at one point and thus have only one possible solution. Hence, the pair of linear equations is consistent.

Answer 2

3/2x + 5/3y = 7 ; 9x – 10y = 14

a1/a2 = 3/2/9 = 1/6

b1/b2 = 5/3/-10 = -1/6 and

c1/c2 = 7/14 = 1/2

Hence, a1/a2 ≠ b1/b2

Therefore, these linear equations are intersecting each other at one point and thus have only one possible solution. Hence, the pair of linear equations is consistent.

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