Question

The pairs of opposite sides of a parallelogram are (3x , 18) and (3y-1, 26), find x and y​

Answer 1

$\bigstar \sf \red{ \underline{Given \: that : } - }$

The pair of opposite sides of a parallelogram are

• 》( 3x ,18 )
• 》 (3y -1 , 26 )

$\bigstar \sf \green{ \underline{To \: Find : } - }$

• 》Find the value of x and y

$\bigstar \sf \purple{ \underline{used \: theorem : } - }$

• The opposite side of parallelogram are equal

$\bigstar \sf \blue{ \underline{Solution: } - }$

given data : - The The pairs of opposite sides of a parallelogram are (3x , 18) and (3y-1, 26) .we have to find the value of x and y .

as we know that

• Opposite side of parallelogram are equal

So , let first we find CD and AB

$\\ \longrightarrow\tt CD \qquad \qquad AB$

$\\ \longrightarrow\tt \: 3y \: - \: 1 \: = \: 26 \qquad \qquad \: \blue{(given)}$

$\\ \longrightarrow\tt 3y \: \: = \: \: 26 + 1 \\ \\ \\ \longrightarrow\tt \: 3y \: \: = \: \: 27 \\ \\ \\ \longrightarrow\tt y \: \: \: = \cancel\frac{27}{3} \\ \\ \\ \red{\boxed{\longrightarrow\tt \frak{y = 9}}}$

Now we find AB and BD

$\\ \longrightarrow\tt AB \qquad \qquad \qquad BD$

$\\ \longrightarrow\tt \: 3x \: \: = \: \: 18 \qquad \qquad \: \blue{(given)}$

$\\ \longrightarrow\tt \: 3x \: \: = 18 \: \\ \\ \\ \longrightarrow\tt \: x = \cancel \frac{18}{3} \\ \\ \\ \green{ \boxed{\longrightarrow\tt \: \frak{x = 6}}}$

Therefore the value of x = 6 and y = 9

Answer 2

$\bigstar \sf \red{ \underline{Given \: that : } - }$

The pair of opposite sides of a parallelogram are : -

》( 3x ,18 )

》 (3y -1 , 26 )

$\bigstar \sf \green{ \underline{To \: Find : } - }$

》Find the value of x and y

$\bigstar \sf \purple{ \underline{used \: theorem : } - }$

The opposite side of parallelogram are equal

$\bigstar \sf \blue{ \underline{Solution: } - }$

given data : - The The pairs of opposite sides of a parallelogram are (3x , 18) and (3y-1, 26) .we have to find the value of x and y .

as we know that

• Opposite side of parallelogram are equal

let first we find GU and SN

$\\ \longrightarrow\tt GU \qquad \qquad SN$

$\\ \longrightarrow\tt \: 3y \: - \: 1 \: = \: 26 \qquad \qquad \: \blue{(given)}$

$\\ \longrightarrow\tt 3y \: \: = \: \: 26 + 1 \\ \\ \\ \longrightarrow\tt \: 3y \: \: = \: \: 27 \\ \\ \\ \longrightarrow\tt y \: \: \: = \cancel\frac{27}{3} \\ \\ \\ \red{\boxed{\longrightarrow\tt \frak{y = 9}}}$

hence GU and SN be 9

Now we find SG and NU

$\\ \longrightarrow\tt SG \qquad \qquad \qquad NU$

$\\ \longrightarrow\tt \: 3x \: \: = \: \: 18 \qquad \qquad \: \blue{(given)}$

$\\ \longrightarrow\tt \: 3x \: \: = 18 \: \\ \\ \\ \longrightarrow\tt \: x = \cancel \frac{18}{3} \\ \\ \\ \green{ \boxed{\longrightarrow\tt \: \frak{x = 6}}}$

hence SG and NU be 6

Therefore the value of x = 6 and y = 9