Physics, asked by shriv381, 9 months ago

The parallax of heavenly body measured from 2 points diametrically opposite on earth's equator in 60 seconds. If the radius of the earth is 6.4*10 raised to 6 metres, determine the distance of the heavenly body from the earth

Answers

Answered by subham21122007
0

Answer:

The parallax of a heavenly body measured from two points diametrically opposite on equator of earth is 1.0 minute. If the radius of the earth is 6400 km,find the distance of the heavenly body from the center of earth in AU.

Explanation:

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Answered by adwaitjoshi28
1

Answer:Given : Parallax angle = 2 minutes

We know that, 

1 minute = 1 / 60 * π / 180 rad

=> 2 min = 2 / 60 * π / 180 rad

=> 2 min  = π / 30 * 180 rad

=> 2 min = π / 5400 rad

=> 2 min = 5.82 × 10⁻⁴ rad

Therefore Parallax angle = 5.82 × 10⁻⁴ rad.

We know that,

Parallax angle = Distance between Two points / Distance of planet

5.82 × 10⁻⁴ = 6400 / Distance of planet from earth

6400 = 6.4 × 10³ km

=> Distance of planet from earth = 6.4 × 10³ / 5.82 × 10⁻⁴

=> Distance of planet from earth = 6.4 / 5.82 * 10³ ⁻ ⁽ ⁻ ⁴ ⁾ km

=> Distance of planet from earth = 1.09 × 10⁷ km ≈ 1.1 × 10⁷ km ( Approx )

Therefore Distance of planet from earth is 1.09 × 10⁷ km.

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Explanation:

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