The parallel lines l and m are cut by a transversal n. If the angle 1 and 2 are (5x-10) and (3x+60) respectively, then find the measures of angle 1 and angle 2.
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can i know where are the angles 1 and 2 situated on l and m lines respectively against n? if both are above/below the lines l and m and on same side of the transversal n, they are corresponding angles and hence they will be equal. then,
(5x-10)=(3x+60)
=>5x-3x =60+10
=>2x =70
=> x =70/2
x=35
if they are on opposite sides of transversal and above/below the lines l and m or they are on same side of transversal but one is above line l and one is below line m or vice versa, then they're called alternative angles.then,
5x-10+3x+60=180
=>8x+50 =180
=>8x =130
=> x =130/8
x=16.25
(5x-10)=(3x+60)
=>5x-3x =60+10
=>2x =70
=> x =70/2
x=35
if they are on opposite sides of transversal and above/below the lines l and m or they are on same side of transversal but one is above line l and one is below line m or vice versa, then they're called alternative angles.then,
5x-10+3x+60=180
=>8x+50 =180
=>8x =130
=> x =130/8
x=16.25
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