Question

The parallel sides of a trapezium are 24cm and 14 cm.The distance between them is

20cm. Find it's​

Answer 1

Question :-

The parallel sides of a trapezium are 24 cm and 14 cm. The distance between them is 20 cm. Find it's area.

Answer :-

Given :-

• Parallel sides of trapezium are 24 cm and 14 cm.

• Distance between them is 20 cm.

To Find :-

• Area

Solution :-

We know that,

Area of trapezium = ½ × sum of parallel sides × height

Substituting the values :-

→ Area = ½ × ( 24 + 14 ) × 20

→ Area = ½ × ( 38 ) × 20

→ Area = 38 × 10

→ Area = 380

Area of trapezium = 380 cm²

Additional information :-

$\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\:triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\ \\ \star\sf Equilateral\:Triangle=\dfrac{\sqrt{3}}{4}(side)^2\end{minipage}}$

Answer 2

$\pmb {\sf {\underline {★Correct \; Question :}}}$

The parallel sides of trapezium are 24cm and 14 cm. The distance between them is 20cm. Find its area.

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$\pmb {\sf {\underline {★ Given :}}}$

• Parallel sides of trapezium = 24 cm & 14 cm.
• Height of trapezium = 20 cm.

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$\pmb {\sf {\underline {★ To \; find :}}}$

• Area of trapezium

$\pmb {\sf {\underline {★ Solution :}}}$ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

$\boxed {\pmb {\sf {\underline {\purple {Area_{(trapezium)} = \dfrac {1}{2} \times {Sum\; of \; parallel \; sides } \times {Height}}}}}}$

$\implies \sf { Area = \dfrac {1}{2} \times {(14+24)} \times 20}$

$\implies \sf { Area = \dfrac {1}{2} \times 38 \times 20 }$

$\implies \sf {Area = 380 \; cm^2 }$