Question

The parallel sides of a trapezium are 6cm and 8cm the distance between them is 4 cm its area is

Answer 1

Step-by-step explanation:

$area = \frac{(sum \: of \: parallel \: side) \times height}{2} \\ \\ area = \frac{(6 +8) \times 4 }{2} \\ \\ = 28 \: {cm}^{2}$

Answer 2

The area of the trapezium is 28 cm².

Given:

The length of parallel sides of the trapezium = 6cm and 8cm.

The distance between the parallel sides = 4cm.

To Find:

The area of the trapezium.

Solution:

We are given that the parallel sides of a trapezium are 6cm and 8cm.

The distance between the parallel sides or the height of the trapezium is 4 cm.

Area of a trapezium = 1/2 x (sum of parallel sides ) x height

The required area of the trapezium = 1/2 x (6 + 8) x 4

= 1/2 x 14 x 4 = 28 cm².

∴ The area of the trapezium is 28 cm².

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