Question

The parallel sides of a trapezium are in the ratio of 2:3.If the area is 750 cm square and height 15 cm .Find the lenghts of the two parallel sides

Answer 1

area of trapezium=
$\frac{a + b}{2} \times h$
here, a and b are parallel sides.,
by given cond.
a=2x, b=3x
area of trape.=
$\frac{2x + 3x}{2} \times 15 \\ 750 = \frac{5x}{2} \times 15 \\ \frac{750 \times 2}{15} = 5x \\ \frac{100 }{5} = x \\ 20 = x$
therefore, a =2x = 2 X 20= 40cm
b =3x = 3 X 20= 60cm
Ans= the lengths of two parallel sides are 40 cm and 60 cm..

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Answer 2

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Answer:

The lengths of the parallel sides are 40cm and 60cm.

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Step-by-step explanation:

Given:

The parallel sides are in the ratio = 2:3

so, Parallel side 1 = 2x

     Parallel side 2 = 3x

Area = 750cm²

Height = 15cm

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To Find:

The lengths of the parallel sides:

Formula for Area of trapezium = $\frac{1}{2}$ x height x (parallel side1 + parallel side2)

750cm² = $\frac{1}{2}$ x 15 x (2x+3x)

750cm² = $\frac{1}{2}$ x 15 x (5x)

750 x 2 = 15 x (5x)

1500 = 15 x (5x)

$\frac{1500}{15}$ = 5x

100 = 5x

$\frac{100}{5}$ = x

∴ 20 = x

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As the parallel sides are in the ratio 2:3..

Parallel Side1 : 2 x 20 = 40cm

Parallel Side2 : 3 x 20 = 60cm

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Solution:

Therefore, the two parallel sides are 40cm and 60cm.

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