The parallel sides of a trapezium are
![6 \frac{1}{2} \: cm \: and \: 5 \frac{1}{2} cm 6 \frac{1}{2} \: cm \: and \: 5 \frac{1}{2} cm](https://tex.z-dn.net/?f=6+%5Cfrac%7B1%7D%7B2%7D++%5C%3A+cm+%5C%3A+and+%5C%3A+5+%5Cfrac%7B1%7D%7B2%7D+cm)
The distance between them is
![2 \frac{2}{3} \: cm 2 \frac{2}{3} \: cm](https://tex.z-dn.net/?f=2+%5Cfrac%7B2%7D%7B3%7D++%5C%3A+cm)
Find the side of a square which has the same area as the trapezium.
Answers
Answered by
0
Step-by-step explanation:
Area of a trapezium=21×(Sum of parallel sides)×distance between them.
=21×(21.5+23.5)×14
=45×7=315sq.cms
∴Area of a trapezium=315sq.cms
Similar questions
Hindi,
3 months ago
English,
3 months ago
Social Sciences,
3 months ago
Hindi,
1 year ago
English,
1 year ago