Question

The parallel sides of a trapezium have lengths 42cmand 26cm and the distance between them is 16cm. Its area is

Answer 1

Area of trapezium = 1/2(a+b)h   {a and b r parallel sides}

A= 42 cm

B= 26

Height= 16 cm

Area= $\frac{(42+26) *16}{ 2} = \frac{68*16}{2} = 68*8$   {After canceling 16 and 2 u will get 8}

A= 544 cm²

KEEP SMILING! KEEP SHINING!!

Answer 2

GiVen:

• Parallel sides = 42 cm and 26 cm.
• Height (distance) = 16 cm.

To Find:

• Area of trapezium = ?

AnSwer:

★ Area of trapezium = 1/2 × ( sum of the parallel sides) × height

$\sf \implies \: \: \dfrac{1}{2} \times (42 + 26) \times 16 \\ \\ \sf \implies \: \: \dfrac{1}{2} \times 68 \times 16 \\ \\ \sf \implies \: \: 68 \times 8 \\ \\ \implies { \underline{ \boxed{ \sf{ \purple{\: \: 544 \: {cm}^{2} }}}}} \: \: \bigstar$

Therefore, area of trapezium is 544 cm².