Question

The parallel sides of a trapezium in the ratio 3:4.If the distance between the parallel sides is 9dm and its distance is 126dm2 find the lengths of its parallel sides

Answer 1

Ratio = 3:4
Let the common multiple be x. So, the parallel sides are 4x and 3x
Height = 9 cm
Area = 126 cm²

Area of trapezium = 1/2 × (Sum of parallel sides × h
126 = 1/2 × (4x+3x) × 9
126 × 2/9 = 7x
28 = 7x

x = 28/7 = 4 cm

Length of parallel sides >
3x = 3(4) = 12 cm
4x = 4(4) = 16 cm

Answer 2

Answer:

By 'distance', I think u meant AREA......

3x = 4.064 × 3 = 12.192 dm²

4x = 4.064 × 4 = 16.256 dm²

Step-by-step explanation:

The parallel sides of a trapezium = 3x and 4x( with the common multiple as x )

The distance b/w the parallel sides = Height = 9 dm

Area = 126 dm²

=  1/2×sum of ║sides × height

=1/2 × 7x × 9 = 126

= 63x = 126 × 2

=x = 252/63

= x = 4 dm

3x = 4 × 3 = 12 dm²

4x = 4 × 4 = 16 dm²

Mark it as the brainliest!!

:)