Question

The parallel sides of an isosceles trapezium are 22 cm and 10 cm and the length of the
non-parallel side is 10 cm. Find the area of the trapezium.​

Answer 1

Step-by-step explanation:

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Answer 2

Given,

The parallel sides of an isosceles trapezium are 22 cm and 10 cm.

The length of the non-parallel side is 10 cm.

Procedure,

To Find The Height,

ACB is A Right Angle Triangle

Hypotenuse^2 = Perpendicular^2 + Base ^2

So, AB^2 = AC^2 + BC^2

(10cm)^2 = AC^2 + (6cm)^2

100cm^2 = AC^2 + 36cm^2

100cm^2 - 36cm^2 = AC^2

64cm^2 = AC^2

AC = 8cm

The Height = 8cm

Solution,

Area of Trapezium = 1/2× (Sum of Parallel Sides) × (height)

Area of Trapezium = [1/2× (22 + 10) × 8]cm^2

= [1/2 × 32 × 8] cm^2

= 144 cm^2