Question

The parallel sides of an isosceles trapezium are 48 cm and 24 cm. Each of its non-parallel side is 26 cm long. Find the area of the trapezium.​

Answer 1

Answer:

Let ABCD be the given trapezium in which AB =48 cm, DC = 24 cm, BC = 26 cm, AD = 15 cm. Through C, draw CF||AD. Now, FB = AB - AF = 48 - 24 = 24 cm. So, it is an isosceles triangle

Step-by-step explanation:

Answer 2

Answer:

Let ABCD be the given trapezium in which AB =48 cm, DC = 24 cm, BC = 26 cm, AD = 15 cm. Through C, draw CF||AD. Now, FB = AB - AF = 48 - 24 = 24 cm. So, it is an isosceles triangle

Step-by-step explanation: