The parallel sides of an isosceles trapezium are in the ratio 2 : 3. if its height is 4 cm and area is 60 cm², find the perimeter.
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Constructing perpendicular line segments from the end points of the side 2x to the side 3x.
Area of the rectangle formed inside the trapezium = 4 × 2x
= 8x cm².
Area of the two triangles formed = 2 × (1/2) × 4 × (x/2)
= 2x cm².
Now, 8x + 2x = 60
x = 6 cm
Length of the Hypotenuse,
h² = (x/2)² + 4² = 3² + 4² = 25
h = 5 cm.
Perimeter of the trapezium is 5 + 5 + 2(6) + 3(6)
= 40 cm.
-WonderGirl
Area of the rectangle formed inside the trapezium = 4 × 2x
= 8x cm².
Area of the two triangles formed = 2 × (1/2) × 4 × (x/2)
= 2x cm².
Now, 8x + 2x = 60
x = 6 cm
Length of the Hypotenuse,
h² = (x/2)² + 4² = 3² + 4² = 25
h = 5 cm.
Perimeter of the trapezium is 5 + 5 + 2(6) + 3(6)
= 40 cm.
-WonderGirl
khushi3eg:
Why did you do (6/2)²?
And could you help me with a figure of this question
(6/2)² can be written as (3)²
I'm sorry I can only edit now. Can't upload photos :\
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