The parallel sides of the trapezium field are 80 m
and 20 m. These sides meet the third side at right
angle . The length of the fourth side is 90 m. If its
cost is rupees 5 to plough per m2 of the field, find the total
cost of ploughing field
ANSWER IS RUPEES 16,770 PROVE HOW
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Answered by
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Answer:
Correct option is
A
Step-by-step explanation:
Correct option is
A
19200
LetthefieldintheshapeofatrapeziumbePQRSwherePS∥QRand∠P&∠Qare90
o
.
HerePS=90m,RQ=30m&SR=100m
Drawa⊥RTfrompointRontoSP.
NowRT=PQandRT∥PQ.
HenceST=90−30=60m
ApplyingPythagoras
′
Theoremin△STR,
TR=
(100
2
−60
2
)
=
(10000−3600)
=
6400
=80m
So,thePQ=heightofthetrapezium=80m
TheareaofthetrapeziumPQRS
=
2
1
×PQ×(RQ+SP)
=
2
1
×80×(90+30)
=40×120
=4800
Costofploughing1field=Rs4
∴Costofplouging4800field
=4×4800
=Rs19200
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