the parallelogram ABCD the area of triangle ABC is 10 square centimetre then the area of ABCD is equal to
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since, ABCD is a //gm and AC is a diagonal
therefore, ar (triangle ABC)=ar (triangle ADC)
now,
Area of //gm ABCD=ar of triangleABC + ar of triangle ADC
=ar of triangle ABC + ar of triangle ABC
=10+10
20 cm^2
therefore, ar (triangle ABC)=ar (triangle ADC)
now,
Area of //gm ABCD=ar of triangleABC + ar of triangle ADC
=ar of triangle ABC + ar of triangle ABC
=10+10
20 cm^2
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