Question

the parameter of a rectangle is 58 CM if its length is 2 more than twice its breadth find the dimensions of the rectangle

Answer 1

LET BREADTH = X

      LENGTH = 2X+ 2

PERIMETER OF RECTANGLE = 2(LENGTH+BREADTH)

           58                                     =  2(2X+2+X)

               58\2                              =   3X+2

               29 - 2                                =    3X

                    27/ 3                              =     X

SO BREADTH = 9 AND LENGTH = 2X+2 = 20