the parameter of a rectangle is 58 CM if its length is 2 more than twice its breadth find the dimensions of the rectangle
Nikita9358:
Is it perimeter?
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LET BREADTH = X
LENGTH = 2X+ 2
PERIMETER OF RECTANGLE = 2(LENGTH+BREADTH)
58 = 2(2X+2+X)
58\2 = 3X+2
29 - 2 = 3X
27/ 3 = X
SO BREADTH = 9 AND LENGTH = 2X+2 = 20
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