Question

the parameter of medium is 26.4 55 x 10 minus power 12c 12 NM to the dielectric constant of the medium will be

Answer 1

Answer:

3x10^13

Explanation:

Permittivity of the medium is 26.55x10 C²/Nm²

Dielectric constant is the ratio of permittivity of medium to permittivity of vaccum (free space).

Experimentally, permittivity of vaccum is 8.85 × 10^-12 C²/Nm².

So dielectric constant is 26.55x10/(8.85x10^-12)

= 3x10^13