The parking charges of a car in a parking lot is Rs 30 for first two hours and Rs. 10 per hour for subsequent
hours. Taking total parking times to be X hours and total charges Rs. Y write a linear equation in two
variables and draw its graph
op 12 er sameter 81000) If the sides of the
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Answer:
y = 10x + 10 ; Rs 60
Step-by-step explanation:
Given, parking charges for the first two hours = ₹30
and for subsequent hours = ₹ 10
Total parking time = xh and total charges = ₹y
Then, according to the given condition,
30 + 10(x-2) = y=> 30 + 10x -20 = y
=>10x + 10-y = 0
=>10x-y+10 = 0 (i)
which is the required linear equation in two variables.
It can also be written as
y = 10x + 10 ,…(i)
Now, for drawing the graph, we need atleast two solutions of the equation.
When x = 0, then y = 10(0) +10 = 10
When x = -1, then y = -10 + 10 = 0
When x = 1, then y = 10(1) + 10 = 20
Parking for five hours will take Rs60
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