Question

The partial pressure of ethane over a solution containing $6.56 * 10^{-3} g$ of ethane is 1 bar. If the solution contains $5.00 * 10^{-2} g$ of ethane, then what shall be the partial pressure of the gas?

NCERT Class XII
Chemistry - Main Course Book I

Chapter 2. Solutions

Answer 1

According to Henry's law, the solubility is directly proportional to the partial pressure of the gas above the solution.

   The partial pressure:  1 bar * 5.00 * 10⁻² gm / 6.56 * 10⁻³ gms
             = 7.62 bar

Answer 2

Hey !!

According to Henry's Law, m = KH × p

CASE - 1

           6.56 × 10⁻²g = KH × 1 bar

(OR)          KH = 6.56 × 10⁻² g bar⁻¹

CASE - 2

           5.00 × 10⁻² g = ( 6.56 × 10⁻² g bar⁻¹) × p

(OR)  

               p = 5.00 × 10⁻² g / 6.56 × 10⁻² g bar⁻¹

FINAL RESULT = 0.762 bar

Hope it helps you !!