The partial pressure of ethane over a solution containing 6.56*10^-3g of ethane is 1 bar.if the solution contains 5.00*10^-2 g of ethane,then what shall be the partial pressure of the gas?
Answers
Answer:
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Explanation:
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According to Henry's law, the solubility of gas in a liquid is directly proportional to the pressure of the gas.
X=Kh×PX is the mole fraction of gas, Kh is the Henry's law constant and P is the partial pressure of the gas.
Also mole fraction of ethane will be directly proportional to its mass.
WP,=W,P
W is the mass of ethane in first solution and P is the partial pressure of ethane in first solution.
W is the mass of ethane in second solution and P
is the partial pressure of ethane in second solution.
6.56×1−3×P,
=5.00×10−2×1 P,=7.6
Hence, the partial pressure of gas will be 7.6 bar.