Question

The partial pressure of ethane over a solution containing 6.56×10–3 g of ethane is 1 bar. If the solution contains 5.00××10–2 g of ethane, then what shall be the partial pressure of the gas?

Answer 1

Hey !!

According to Henry's Law, m = KH × p

CASE - 1

           6.56 × 10⁻²g = KH × 1 bar

(OR)          KH = 6.56 × 10⁻² g bar⁻¹

CASE - 2

           5.00 × 10⁻² g = ( 6.56 × 10⁻² g bar⁻¹) × p

(OR)  

               p = 5.00 × 10⁻² g / 6.56 × 10⁻² g bar⁻¹

FINAL RESULT = 0.762 bar

Hope it helps you !!