Question

The particle is moving in a horizontal circle of radius 50cm. It has angular speed of 12 rad/s . the magnitude of linear velocity of the particle is​

Answer 1

Given:

Particle moving in a horizontal circle of radius 50 cm has an angular speed of 12 rad/s.

To find:

Magnitude of linear Velocity

Calculation:

Magnitude of Linear Velocity can be calculated by the product of magnitude of angular velocity (i.e. angular speed) and the radius of the circular trajectory.

$\sf{ \therefore \: | \vec{v}| = | \vec{ \omega}| \times r}$

$\sf{ = > \: | \vec{v}| = 12 \times \dfrac{50}{100} }$

$\sf{ = > \: | \vec{v}| = 12 \times \dfrac{1}{2} }$

$\sf{ = > \: | \vec{v}| =6 \: m {s}^{ - 1} }$

So, final answer is:

$\boxed{\bf{magnitude \: of \: linear \: vel. = | \vec{v}| =6 \: m {s}^{ - 1} }}$