the particle is thrown up vertically with a velocity of 50m/s what will be iys velocity at the highest point of the journey how high would the particle rise what time would it take to reach the highest point.
Answers
Answered by
8
Hi frnd...
At the highest point it's velocity will be 0.
To find time:
v=u+at
0=50+(-10)t
10t=50
t=5 sec.
To find height:
S=ut+0.5at^2
S=250+(-5)25
S=250-125
S=125m
Hope it helped u!!!
At the highest point it's velocity will be 0.
To find time:
v=u+at
0=50+(-10)t
10t=50
t=5 sec.
To find height:
S=ut+0.5at^2
S=250+(-5)25
S=250-125
S=125m
Hope it helped u!!!
Answered by
11
Check this attachment :-)
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aryan014:
osm ;)
hmm
osm ;)
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