Question

The particular integral of the differential equation F(D)y=Q is equual to
(A) 1/F(D)
(B) 1.Q/F(D)
(C) Q.F(D)
(D) all of the above​

Answer 1

Answer:

അറിയുല പറ്റിച്ചേ

Answer 2

SOLUTION

TO CHOOSE THE CORRECT OPTION

The particular integral of the differential equation F(D)y=Q is equal to

(A) 1/F(D)

(B) 1.Q/F(D)

(C) Q.F(D)

(D) all of the above

EVALUATION

Here the given differential equation is

F(D)y = Q

Now the complementary function is obtained by solving the differential equation F(D)y = 0

Also the particular integral is obtained by solving

$\displaystyle \sf{ = \frac{1}{Q}F(D)}$

FINAL ANSWER

Hence the correct option is

$\displaystyle \sf{ (B) \: \: \: \frac{1}{Q}F(D)}$

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