Question

The path of a train A is given by the equation 3x+4y-12=0 and path oftrain B is given by the equation 6x+8y-48=0. Represent the situation graphically.

Answer 1

Answer:

Refer the attached figure.

Step-by-step explanation:

Given : The path of a train A is given by the equation $3x+4y-12=0$ and path of train B is given by the equation $6x+8y-48=0$.

To find : Represent the situation graphically?

Solution :

The path of a train A is given by the equation $3x+4y-12=0$ ...(1)

The path of a train B is given by the equation $6x+8y-48=0$ ...(2)

Now, we plot the equations with the help of graphing tool.

Equation 1 - $3x+4y-12=0$ represent by red line passing through (0,3) and (4,0).

Equation 2 - $6x+8y-48=0$ represent by blue line passing through (0,6) and (8,0).

Both the equations represented are parallel to each other.

Refer the attached figure below.

Answer 2

Step-by-step explanation:

Equation of path (A) : 3x+4y−12=0

⇒x-intercept of (A) =4

⇒y-intercept of (A) =3

⇒Slope of (A) = -3/4

Equation of path (B) : 6x+8y−48=0

⇒x-intercept of (B) =8

⇒y-intercept of (B) =6

⇒Slope of (B) = -6/8 = -3/4

⇒Both the paths are parallel as there slopes are equal.