Question

The path of a train A is given by the equation 3x+4y-12=0 and the path of another train B is given by the equation 6x+8y-48=0. Represent this situation graphically.

Answer 1

The image of the graph is attached below.

Explanation:

Given that the path of a train A is given by the equation $3 x+4 y-12=0$

The path of train B is given by the equation $6 x+8 y-48=0$

We need to represent the situation graphically.

To plot the graph let us determine the x and y intercepts for the two equation $3 x+4 y-12=0$ and $6 x+8 y-48=0$

Let us consider the equation $3 x+4 y-12=0$

Substituting $x=0$, we have,

$3 (0)+4 y-12=0$

                  $4 y=12$

                    $y=3$

Now, substituting $y=0$, we have,

$3 x+4 (0)-12=0$

                  $3 x=12$

                    $x=4$

Thus, the coordinates are $(0,3)$ and $(4,0)$

Now, let us consider the equation $6 x+8 y-48=0$

Substituting $x=0$ , we have,

$6 (0)+8 y-48=0$

                  $8 y=48$

                    $y=6$

Now, substituting $y=0$, we have,

$6 x+8 (0)-48=0$

                  $6 x=48$

                    $x=8$

Thus, the coordinates are $(0,6)$ and $(8,0)$

Now, plotting these coordinates in the graph, we can see that the two lines are parallel to each other.

learn more:

(1) The path of a train A is given by the equation 3x+4y-12=0 and path oftrain B is given by the equation 6x+8y-48=0. Represent the situation graphically.

brainly.in/question/1258354

(2) The path of a train A is given by the equation 3x + 4y – 12 = 0 and the path of another train B is given by the equation 6x + 8y – 48 = 0. Represent this situation graphically.

brainly.in/question/15918163