Question

The pd. between the ends of a wire of resistance 5 ohm, if 720 coulomb of charge passes
through it per minute.
​

Answer 1

Answer:

V=60V

Explanation:

I=720/60

I=12A

SINCE V=IR

SO,

V=5×12

V=60V

Answer 2

The potential difference between the ends of a wire is 60 volts.

Explanation:

It is given that,

Resistance, R = 5 ohms

Charge, q = 720 C

Time, t = 1 min = 60 s

We know that charge flowing per unit charge is called current in the circuit. It is given by :

$I=\dfrac{q}{t}$

$I=\dfrac{720\ C}{60\ s}$

I = 12 A

Let V is the potential difference between the ends of a wire. It can be calculated using Ohm's law as :

V = IR

$V=12\ A\times 5\ \Omega$

V = 60 Volts

So, the potential difference between the ends of a wire is 60 volts. Hence, this is the required solution.

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Ohm's law

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