The percentage by mass of cation in ammonium chromate will be (At. mass of Cr=52, N=14, O=16) ?
A] 13.4%,
B] 30.4%,
C] 25.7%
D] 23.7%
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Answer:Ammonium chromate is (NH4)2CrO4
molar mass is = (14+4)2+52+64=152
Here cation is NH4+
percentage by mass of cation= molecular weight of cation/molecular weight of ammonium chromate
% by mass of cation = 36*100/152
= 23.7%
Therefore option (D) is correct.
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