Question

the percentage composition of water in caso4.2h2o​

Answer 1

The percent composition of water in the given compound is 20.93 %

Explanation:

We are given:

Atomic mass of calcium = 40 u

Atomic mass of sulfur = 32 u

Atomic mass of oxygen = 16 u

Atomic mass of hydrogen = 1 u

To calculate the percentage of water in $CaSO_4.2H_2O$ , we use the equation:

$\text{Mass percent of water}=\frac{\text{Mass of water}}{\text{Mass of }CaSO_4.2H_2O}\times 100$

Mass of $CaSO_4.2H_2O=[40+32+(4\times 16)+2((2\times 1)+16)]=172u$

Mass of $2H_2O=2\times [(2\times 1)+16)]=36u$

Putting values in above equation, we get:  

$\text{Mass percent of water}=\frac{36u}{172u}\times 100\\\\\text{Mass percent of water}=20.93\%$

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Answer 2

Answer:

hope it helps

Explanation: