Question

The percentage error in the measurement of diameter of a sphere is 5%. The percentage error in the measurement of its volume will be

Answer 1

Answer:

1.5 %

Explanation:

Correct option is

D

1.5%

Volume (V)=

3

4

πr

3

Taking log.

log(V) =log(

3

y

π)+3logr

Differentiating

V

δV

=3

r

δr

V

δV

×100=3

r

δr

×100…(i)

r

δr

×100=0.5%

putting in (i)

V

δV

×100

=3×0.5

=1.5%

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