Math, asked by meghavs23, 4 months ago

The percentage error in the measurement of the radius of sphere is 2cm. Find the percentage error in the measurement of its area and volume

Answers

Answered by rajshree317

1

Answer:

Percentage error in radius is given as 2% i.e.

Δr/r×100=2 %

Volume of sphere V= (4π/3)*r^3

Percentage error in volume =ΔV/V×100=3×Δr/r×100=3×2=6 %

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