the percentage errors in the measurement of mass and speed are 3% and 4% respectively. the maximum percentage error in kinetic energy will be -
a. 11%
b.10%
c.8%
d.2%
please answer fast
Answers
Answered by
2
I think 10
is the correct answer
Answered by
11
Explanation:
We know
K.E.=1/2 mv^2
Given,
∆m/m × 100=3.
∆v/v ×100=4.
Now,
∆E/E = +-{∆m/m +( 2 × ∆v/v)}
∆E/E = +-(3+ 2×4)
∆E/E = 3+8 =11
Multiplying by 100 ,we get percentage error in K.E.= 11%
Ans-option b
Hope it will help you..
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