The percentage increase in the area of a rectangle, if each of its sides is increased by 20%
A) 22%
B) 33%
C) 44%
D) 55%
Answers
Answered by
10
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Answer: C) 44%
Explanation:
Let original length = x metres and original breadth = y metres.
Original area = xy sq.m
Increased length = 120100 and Increased breadth = 120100
New area = 120100x*120100y=3625xy m2
The difference between the Original area and New area is:
3625xy-xy
1125xy Increase % =(1125xyxy)*100= 44%
Answered by
15
The percentage increase in the area of a rectangle, if each of its sides is increased by 20%
A) 22%
B) 33%
C) 44%
D) 55%
Answer = Option C
Explanation:
Let original length = x metres and original breadth = y metres.
Original area = (xy) m2.
New length =(120/100x)m=(6/5x)m.
New breadth =(120/100y)m=(6/5y)m.
New Area =(6/5x × 6/5y)m2=(36/25xy)m2.
The difference between the original area = xy and new-area 36/25 xy is
= (36/25)xy - xy
= xy(36/25 - 1)
= xy(11/25) or (11/25)xy
Hence, Increase % =(11/25xy × 1/xy × 100)%= 44%.
A) 22%
B) 33%
C) 44%
D) 55%
Answer = Option C
Explanation:
Let original length = x metres and original breadth = y metres.
Original area = (xy) m2.
New length =(120/100x)m=(6/5x)m.
New breadth =(120/100y)m=(6/5y)m.
New Area =(6/5x × 6/5y)m2=(36/25xy)m2.
The difference between the original area = xy and new-area 36/25 xy is
= (36/25)xy - xy
= xy(36/25 - 1)
= xy(11/25) or (11/25)xy
Hence, Increase % =(11/25xy × 1/xy × 100)%= 44%.
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