Question

The percentage loss in weight after heating a pure sample of potassium chlorate will be

Answer 1

KClO4-->KCl+2O2

Now, by this reaction we can say that the loss In weight of KClO4 is due to libration of O2 .

M.Wt. of KClO4 is --> 138.5

so,

138.5g KClO4--> 64g of O2

1g KClO4-->64/138.5 g of O2

100g KClO4-->4.62x100

=46%

Explanation:

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