Question

the percentage of pie character in the orbital forming p_p bonds in p4 is​

Answer 1

Answer:

75%

Explanation:

Phosphorus atom is sp³ hybridized in P₄ usually.

Therefore,

Percentage of p character = 75%

Hope it helps!

Answer 2

Answer:

75%

The percentage of p-character in forming P-P bonds in P4 molecule is: 0. In forming P4molecule, P atom uses sp3 hybrid orbitals. Thus, p-character in hybrid orbitals is 75%.