Question

the percentage of silica in sodium silicate is approximately (atomic weight of si=28)

Answer 1

Chemical formula of sodium silicate is Na2Sio3
Then total mass of sodium silicate is =122 u
%of Si =28/122 *100 = 22.9%

Answer 2

Answer : The percentage of silicon in sodium silicate is, 23 %

Solution : Given,

Molar mass of silicon (Si) = 28 g/mole

Molar mass of $Na_2SiO_3$ = 122.06 g/mole

As there are two atoms of sodium, one atom of silicon and 3 atoms of oxygen.

Now we have to determine the percentage of silicon in sodium silicate.

$\%\text{ of silicon}=\frac{\text{Mass of silicon}}{\text{Mass of }Na_2SiO_3}\times 100$

Now put all the given values in this formula, we get the percentage of silicon.

$\%\text{ of silicon}=\frac{28g}{122.06}\times 100=22.93\approx 23$

Therefore, the percentage of silicon in sodium silicate is, 23 %